Last updated 2004-06-28 by Roedy
Green ©1996-2004 Canadian Mind Products
Java definitions: 0-9 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
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| Mutable Primitives | Immutable Objects |
|---|---|
| boolean | Boolean |
| ordinary signed byte | Byte |
| unsigned byte | Byte |
| short | Short |
| char | Character |
| int | Integer |
| long | Long |
| float | Float |
| double | Double |
| char[] | String |
Interconverting byte [] and String is tricky because there is always an implied encoding translation. "8859_1" encoding simply chops the high byte off or pads the high byte with 0s, what newbies erroneously imagine happens all the time.
String s = "abc"; // string -> byte[] byte [] b = s.getBytes( "8859_1" /* encoding */ ); // byte[] -> String String t = new String( b , "Cp1252" /* encoding */ );
Interconverting char[] and String is easier because there is no encoding involved.
String s = "abc" ; // string -> char[] char[] ca = s.toCharArray(); // char[] -> String String s = new String( ca );
The radix feature of the toString and parseInt methods lets you handle hexadecimal numbers. Just set the radix to 16.
Strings and StringBuffers can be interconverted.
StringBuffer q; String s; q = new StringBuffer(s); s = new String(q); s = q.toString();
Rounding often surprises because fractions like 0.1 cannot be precisely be represented in IEEE floating point format. Often you find yourself having to add tiny numbers just prior to printing to get the desired effects.
// Rounding to an integer: long n = Math.round(d); double d = Math.rint(d); // Rounding to two decimal places: long n = Math.round(d *100.); /* keep as "pennies" */ double d = Math.rint (d *100.)/100.;
The standard conversions give you no leading blanks or leading zeroes. Here is a code snippet to convert an integer to string padded with leading left zeroes. With an obvious modification it would give you lead blanks.
public static String toLZ( int i, int len ) { // converts integer to left-zero padded string, len chars long. String s = Integer.toString(i); if ( s.length() > len ) return s.substring(0,len); else if ( s.length() < len ) // pad on left with zeros return "000000000000000000000000000".substring(0, len - s.length ()) + s; else return s; } // end toLZ
JDK 1.0.2 has no function like C's printf that lets you control how many positions and decimal places you want in your output. You have to roll your own.
JDK 1.1 has formatting picture classes such as java.util.DateFormat, SimpleDateFormat and DecimalFormat.
Formatting is such a common request, you might attain sainthood if you wrote a formatting class that gives you all the power of printf without the overhead of parsing strings for % produce a string. e.g.
public class Form { static String display (int value , int width , int decimalPlaces , int base , boolean leadZeroes); static String display (int value , int width , int decimalPlaces , int base); static String display (int value , int width , int decimalPlaces); static String display (int value , int width); static String display (int value); static String display (double value , int width , int decimalPlaces); static String display (double value , int width); static String display (double value); }
Java has no built-in methods for reading data of the form: 123 456,-4.
You have to roll your own method. Use java.io.StreamTokenizer or java.util.StringTokenizer, perhaps in combination with readLine to get your data into strings. StreamTokenizer has bells and whistles to deal with parsing source code, including white space, comments and numbers. StringTokenizer just splits the text up based on delimiter characters. Then use the conversion methods in the table above to convert to integers etc. See below for a simplified examples of how you would do this.
// Read space or comma-delimited file of integers // Convert from ASCII to internal binary ... BufferedReader in = new BufferedReader(new FileReader("C:\\temp\\foo.in" ) ); StreamTokenizer st = new StreamTokenizer(in); // process the entire file, of space or comma-delimited ints int found = StreamTokenizer.TT_NUMBER; while ( found != StreamTokenizer.TT_EOF ) { found = st.nextToken (); if ( found == StreamTokenizer.TT_NUMBER ) { int i = (int)st.nval; System.out.println(i); } // end if } // end while
// Read space-delimited file of integers // Convert from ASCII to internal binary ... BufferedReader in = new BufferedReader(new FileReader( "C:\\temp\\foo.in" ), 4096 /* buffsize */ ); String aLine = in.readLine(); StringTokenizer st = new StringTokenizer(aLine); // process one line worth of space-delimited integers while ( st.hasMoreTokens() ) { String s = st.nextToken(); int i = Integer.parseInt(s); System.out.println(i); } // end while
Binary is a compact, machine-friendly, human-unintelligible format. For human readable i/o, Java works with Strings of characters. You separately convert these to and from internal binary format e.g. int. See the conversion Amanuensis for how.
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